If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5n^2-81=-12n
We move all terms to the left:
5n^2-81-(-12n)=0
We get rid of parentheses
5n^2+12n-81=0
a = 5; b = 12; c = -81;
Δ = b2-4ac
Δ = 122-4·5·(-81)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-42}{2*5}=\frac{-54}{10} =-5+2/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+42}{2*5}=\frac{30}{10} =3 $
| 36x+(-15)=705 | | 4=5x–6x+3 | | -4+3x+7x=-24 | | 36x+-15=705 | | -10+4x+x=-5 | | 7+x+5x=43 | | 7864y+7658y=8 | | 4(4x+8)=20 | | 7x+3=11-9 | | 6c=9c^2 | | 2/3(15u-6)=14u | | (x+2)(7x-5)=0 | | 3w*w=306 | | 3w-3*w=306 | | 14m-8=50 | | 4(x-2)=12(x-2) | | 14(x-2)=42 | | 5(g-2)=3(g+2( | | 6(m+2)+7=5(m-1) | | 12x-66+15=3x=12 | | x+3/6-4/3=x-2/4 | | 5(g-2)=3(g | | 5(4x-4)=120 | | 40x-20=14x | | F(x)=3x+2x+7 | | 4m-2(m-2)=20 | | 2w+2(3w+6)=32 | | 150=105+10.5x | | 8(4-x)=7x+2= | | 65+60+50+35+x+x+x=180 | | 14x-12(x-1)=20 | | 17x-12=114/3x |